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7n^2-47n-14=0
a = 7; b = -47; c = -14;
Δ = b2-4ac
Δ = -472-4·7·(-14)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-51}{2*7}=\frac{-4}{14} =-2/7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+51}{2*7}=\frac{98}{14} =7 $
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